If you read my previous post, I gave you a math problem from the Florida Real Estate Exam. I hope you learned how to do that one. If you did not, check out my videos on You Tube. This one is not on You Tube because this is an old old problem that the test writers must have brought up from the archives.
A man bought three houses for a total of $44,000. The second house cost six thousand dollars more than the first house. The third house cost four thousand dollars more than the second house. What is the price of the first house? A. $9333.33 B. $20000 C. $10000 D. $28000
Please post how to do it in comments. Do not go take the Florida real estate exam without knowing how to do this unless you call Kathy at 407 822 3926, get the answer and memorize it.
http://www.climerrealestateschool.com/ Orlando, Florida
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ReplyDelete1st-X
ReplyDelete2nd-X+6000
3rd-X+10000
X+(X+6000)+((X+6000)+4000)=44000
3X+16000=44000
3X=28000
X=28000:3=9333.33
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